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OHM'S LAW CHUNGCHANG A RESISTANCE NIHPHUNG BULPUI
Wires emaw eng thil pawh current kal theihna chi tawh phawt chu heng nihphung te hian current a ei ral theih dan a hril-
the length of the conductor ( Kan Wires/Materials hman sei dan azirin)
the material of the conductor (Eng thil nge kan hman, Copper nge Steel, Nichrome etc)
the temperature of the material (A lum leh vawt dan azirin current kal a chak in a chaklo thei)
the cross-sectional area of the conductor (Kan Wire / Materials hman len zawng (Diameter) a zir in.
Hetiangin kan chhut chhuak thei ang. A Formula chu –
R = ρ l / A (1)
R = resistance (ohms, Ω)
ρ = resistivity (ohm meter, Ω m)
l = length of conductor (m)
A = cross-sectional area of conductor (m2)
Resistivity of some Common Conductors
Aluminum: 2.6 x 10-8 Ω m
Copper: 1.7 x 10-8 Ω m
Entirnan : Copper wire 10 Meter a sei, 0.8mm2 a lian a awm a, A Current dodal theihna Resistance
Engzatnge ni ang?
Soln - R = (1.7 x 10-8 Ω m) (10 m) / ((0.8 mm2)(10-6 m2/mm2))
= 0.21 Ω Ans
Wires emaw eng thil pawh current kal theihna chi tawh phawt chu heng nihphung te hian current a ei ral theih dan a hril-
the length of the conductor ( Kan Wires/Materials hman sei dan azirin)
the material of the conductor (Eng thil nge kan hman, Copper nge Steel, Nichrome etc)
the temperature of the material (A lum leh vawt dan azirin current kal a chak in a chaklo thei)
the cross-sectional area of the conductor (Kan Wire / Materials hman len zawng (Diameter) a zir in.
Hetiangin kan chhut chhuak thei ang. A Formula chu –
R = ρ l / A (1)
R = resistance (ohms, Ω)
ρ = resistivity (ohm meter, Ω m)
l = length of conductor (m)
A = cross-sectional area of conductor (m2)
Resistivity of some Common Conductors
Aluminum: 2.6 x 10-8 Ω m
Copper: 1.7 x 10-8 Ω m
Entirnan : Copper wire 10 Meter a sei, 0.8mm2 a lian a awm a, A Current dodal theihna Resistance
Engzatnge ni ang?
Soln - R = (1.7 x 10-8 Ω m) (10 m) / ((0.8 mm2)(10-6 m2/mm2))
= 0.21 Ω Ans